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It is often mistakenly thought that “efficiency” is synonymous with the efficiency factor. This is only true if both quantities on the right of the equation
efficiency = benefit / effort
have the dimension of “energy” or “power”. But very often the provided benefit has nothing to do with energy. For example, the benefit can be a mileage (unit “miles”). For example, the effort can be the fuel required (unit “gallons”) and the efficiency of this service will be given as
mileage / (fuel consumption)
Measured in “miles/gallon”. In Europe the inverse value
effort coefficient = 1/efficiency
has become established, i.e. the specific fuel consumption in litres/(100 km).
For example, the efficiency factor of heating boilers cannot be increased to more than 100% (law of energy conservation) and today values in the range of 90% have already been achieved. But still the efficiency of the heating application (e.g. heated space/heating energy) can be improved almost as far as you want by applying improved thermal protection. If only the efficiency factor was of importance, there would be no potential for saving a lot of energy with heating. Based on a broader understanding of this, it is evident that the required “heating demand” can be reduced to near zero by using better insulation, therefore there is a very great efficiency potential here. That this also works in practice, has been demonstrated by numerous Passive Houses that have been built and are now inhabited.
This also applies for many other energy applications; especially the final use of energy at the end of the supply chain provides a significant potential for better efficiency. For example:
|Fig 1: The figure illustrates that increased efficiency is more than just improving
the efficiency factor. The efficiency factor of the compressor (on the right) in the
highly efficient refrigerator is increased - however, better insulation of the casing
significantly improves efficiency. This considerably improves the cooling volume/
“cooling energy” ratio. Strictly speaking, there is no such thing as “cooling ener-
gy”, this is the quantity of heat which has to be actively removed.
A consistent analysis of all services provided through the use of energy today shows that from the physics perspective, this mainly consists of maintaining a state of non-equilibrium. However, by intelligent process management, this can be transformed into an almost stable equilibrium state. An extremely small amount of energy is required for this. For example:
Transportation efficiency: Different vehicles consume different amounts of fuel for the same service (transporting 1 person over a distance of 100 km):
→ 12 litres/100 km per person (a relatively old car)
→ 6 litres/100 km per person (an average modern car)
→ 3 litres/100 km per person (a modern efficient car)
→ 1 litre/100 km per person (prototype of the 1-litre car or “Hypercar”)
→ 0 litres/100 km per person (a frictionless vehicle on a brachistochrone curve; see Fig 2
|Fig 2: An intriguing experiment: the body which follows the longer path through the trough reaches the end more quickly.
No energy is required for this as long as the process is reversible.
For those, who want to see the proof - it's at the end of this page
| Brachistochrone curve?
Even Galilei knew about it: it’s the fastest path from A to B without using any energy in a homogeneous gravitational field.
→ Do you want to know more? Download the following article: "Wissenschaft, Kultur und Lebensart rund um das Passivhaus" (in German) which not only explains about the brachistochrone curve but also about exergy and anergy and why Galilei still hasn't managed to become fully established in daily life in contrast with Aristoteles.
For most activities, energy is not required at all, or at least only a very small amount of energy is needed – but only when losses can be consistently avoided. This is because these activities do not have an energy dimension and in fact consist of maintaining a particular state.
Improved energy efficiency therefore can almost completely substitute the energy previously required. “Energy efficiency” is almost equivalent to a new energy source - but only almost, because energy efficiency is much better. Energy efficiency is clean, inexhaustible and free during the period of use. Energy efficiency can be applied everywhere. And: we ourselves can “produce” energy efficiency everywhere on the globe; it is integrated in smart products from the very beginning - for the benefit of the user (lower running costs and increased comfort), with advantages for the manufacturers (higher quality and therefore higher added value) and advantages for the national economy (domestic employment) and for the environment (climate protection).
There can only be winners - even the suppliers of conventional energy can be winners if an adequate time horizon is adopted: e.g. the supply of fuel oil will last much longer and can be sustained with lower risks if the efficiency of use is significantly improved.
Energy efficiency can be significantly improved in many areas, as can be seen in this analysis of the energy balance.
Appendix: Proof for statement in fig.2
We call the velocity on the horizontal path v0. This velocity has only a horizontal (x-)component which is constant according to Galilei's law (first Newtons law).
Now consider the body going through the trough. It starts with the same horizontal velocity. But it gains energy from the gravitational field, the energy conservation law gives for the total kinetic energy at a place x
1/2 m v(x)2 = 1/2 m v02 - m g z(x)
Here v(x) is the total velocity at place x and z(x) is the vertical coordinate of the lower body, z=0 is the hight of the plane. Note that z(x)<0 for all x>0 and x smaller as the goal coordinate. The additive energy term on the right side is therefore always positiv, energy is gained from the gravitational field at all places for the body on the lower lane. Thus, the total velocity v(x) is always higher than the velocity v0.
Now, as the body rides down the slope, kinetic energy in z-direction is transformed into kinetic energy in x-direction. How high wil the vx(x) be? See the vector diagramm in Fig. 2: The total velocity is tangential to the slope:
Thus, the kinetic energy in x-direction is beeing increased - therfore, not only v(x)>v0, but also vx(x) > v0 for all x on the downward slope. Time reverse symmetry gives, that at the upward slope all x-velocities are equal to the x-velocities at the same hight on the downward slope. This means, that at any point in the lower path the x-component of the velocity is higher than the x-velocity of the body on the plane. If sgoal is the horizontal distance of the goal, the time for the upper body will be
tupp = sgoal / v0
the time for the lower body, however, will be shorter, because it's x-velocity is always greater than the velocity of the upper body:
tBra = ∫1/vx(x) dx < ∫1/v0dx = sgoal / v0= tupp